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White light is passed through a diffraction grating that has the spacing between the slits of 4x10^6m. On each side of the white central maximum, a spectrum of colors is observed. What is the wavelength of the light observed at an angle of 7.00° in the first-order bright fringes?

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Answer:

The wavelength of the light is 487477.37 m.

Step-by-step explanation:

Given that,

Spacing between the slits
d= 4*10^(6)\ m

Angle = 7.00°

We need to calculate the wavelength

Using formula of wavelength


d\sin\theta=n\lambda

Where, d = distance between the slits

n = order bright fringes

Put the value into the formula


\lambda=(d\sin\theta)/(n)


\lambda=(4*10^(6)*\sin7.00)/(1)


\lambda=487477.37\ m

Hence, The wavelength of the light is 487477.37 m.

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