Question

Write an equation for the line that passes through (2, 3) and (3, 6).

Answer 1

y=3x-3

Explanation:

equation of the line:

y = mx+b

m=slope=(y2-y1)/(x2-x1)

we have: (2, 3) and (3, 6)

we will find the slope:

m=(6-3)/(3-2)

m=3/1 = 3

using the point (2,3) we will find "b"

3=3(2)+b

3-6=b

b= -3

so the equation is: y=3x-3