Question

What is the value of x in the equation
`(1)/(5)x -(2)/(3)` y = 30, when y = 15?

Answer 1

Answer:
`x=200`

Explanation:

You have the following equation:

`(1)/(5)x -(2)/(3) y = 30`

In order to find the the value of the variable "x" when
`y=15`, you need to substitute this value of "y" into the equation and then you must solve for "x".

Applying this procedure, you get:

`(1)/(5)x -(2)/(3) y = 30\\\\(1)/(5)x -(2)/(3) (15) = 30\\\\(1)/(5)x -(30)/(3) = 30\\\\(1)/(5)x -10 = 3\\\\(1)/(5)x=30+10\\\\x=5(40)\\\\x=200`

Answer 2

x= 200

Explanation:

The given equation is:

1/5 x - 2/3 y = 30

The value of y is 15

Put the value of y in the given equation:

1/5 x - 2/3(15) = 30

1/5 x- 10 = 30

Take the L.C.M of the denominator

x-50/5 = 30

Move the denominator to the R.H.S

x-50 = 30*5

x-50 = 150

Combine the like terms

x= 150+50

x = 200

The value of x is 200...