Question

Consider a planet with twice the mass and twice the radius of Earth. Its escape speed is how many times that of Earth?

A. 0.25

B. 0.5

C. 1

D. 2

E. 4

Answer 1

1

Step-by-step explanation:

The escape speed of the earth is given by
`\sqrt{(2GM)/(R)}` here G is gravitational constant and M is the mass and R is the radius of the earth

Now in the question it is said that if mass is increases twice and radius is also becomes twice so escape speed
`\sqrt{(2G2M)/(2R)}=\sqrt{(2GM)/(R)}` it is the same before the changing the mass and radius of the earth so the escape speed will be same that is 1 times of the earth