Question

A roller coaster is traveling at 13m/s when it approaches a hill that is 400 m. long. Heading down the hill, it accelerates 4.0m/s^2 . What is the final velocity of the roller coaster?

Answer 1

58.0 m/s

Step-by-step explanation:

We can solve the problem by using the following SUVAT equation:

`v^2 = u^2 +2as`

where

v is the final velocity of the roller coaster

u = 13 m/s is the initial velocity

a = 4.0 m/s^2 is the acceleration

s = 400 m is the displacement

Substituting and solving for v, we find

`v=√(u^2 +2as)=√((13)^2 +2(4)(400))=58.0 m/s`