Question

A doubly ionized lithium atom (Li2+) has only one electron in orbit about the nucleus. What is the radius of the ion when it is in the n = 4 excited state?

Answer 1

`9.40* 10^(-11)`

Step-by-step explanation:

n = order of excited state of the ion = 4

z = atomic number of lithium atom = 3

Radius of ion in nth excited state is given as

`r_(n) = (5.29* 10^(-11)) (n^(2))/(z^(2))`

for n = 4 and z = 3

inserting the values

`r_(4) = (5.29* 10^(-11)) (4^(2))/(3^(2))`

`r_(4) = 9.40* 10^(-11)`