Question

Based on following data, Angular acceleration of the tibia 450 rad/sec 2 The mass moment of inertia for the tibia is 0.40 Nm sec 2 The perpendicular distance between patellar tendon and the center of rotation is 0.045m Determine the muscle force acting on patellar tendon. Show all works

Answer 1

4000 N

Step-by-step explanation:

We have given angular acceleration
`\alpha =450rad/sec^2`

Moment of inertia = 0.40 Nm

The distance d from the center of rotation is
`d=0.045 m`

We have to find the muscle force F

From torque equation we know that
`Fd=I\alpha`

`F* 0.045=0.40* 450`

`F=4000\ N`