Question

What is the concentration of hydronium ions in a solution given that the concentration of hydroxide ions is 2.31 × 10 -4 M?

Answer 1

Answer: 4.32 X
`10^{^(-11)}`

Explanation: Given concentration of hydroxide ions = 2.31 x
`10^{^(-4)}`

As we know that Kw ( ionic product of water) at 25 °C =
`10^{^(-14)}`

and Kw is the product of concentration of hydronium ions and hydroxide ions.

Thus,

Kw =
`H_{_(3)}O^{^(+)}`
`OH^{^{^(-)}}`

`10^{^(-14)}` =
`H_{_(3)}O^{^(+)}` X 2.31 x
`10^{^(-4)}`

`10^{^(-14)}` / 2.31 x
`10^{^(-4)}` =
`H_{_(3)}O^{^(+)}`

`H_{_(3)}O^{^(+)}` = 4.32 X
`10^{^(-11)}`

Thus, the concentration of hydronium ions in a solution = 4.32 X
`10^{^(-11)}`