Answer:
(a) 17450.8 J (B) 1.239 sec
Step-by-step explanation:
We have given power output =8 KW
Heat expelled = 10994 j
Efficiency =37% = 0.37
(A) We know that efficiency
![\eta =1-(heat\ expelled)/(heat\ input)]()
![0.37=1-(10994)/(heat\ input)]()
Heat input =17450.8 J
(B) Work done by the engine is = 17450.8-10994=6456.8 j
Power output is given by 8 KW =8000 W
So time for each cycle is
![(8000)/(6456.8)=1.239 sec](https://img.qammunity.org/2020/formulas/physics/college/spfaaf3oqtu7er02y4jx6ni0zql87gdl94.png)