Answer: 68.27%
Step-by-step explanation:
We assume that the world human population heights follow a perfect normal distribution.
Given : Population mean :

Standard deviation :

Let X be the random variable that represents the height of population.
Z-score :

For x=130

For x=170

By using the standard normal distribution table for z , we have
P-value =


Hence, the percentage of the population would have a height between 130 and 170 = 68.27%