Question

In an experiment to measure acceleration g due to gravity, two values, 9.95m/s^2 and 9.82 m/s^2, are determined. Find: (a) the value of g for this experiment (b) percent error of their mean

Answer 1

Part a)

g = 9.885 m/s/s

Part b)

error = 0.66 %

Step-by-step explanation:

Part a)

The experimental values of acceleration due to gravity is given as

`g_1 = 9.95 m/s^2`

`g_2 = 9.82 m/s^2`

now we know that the value of g is the mean value of all the readings

so we have

`g = (g_1 + g_2)/(2)`

`g = (9.95 + 9.82)/(2)`

`g = 9.885 m/s^2`

Part b)

error in both readings of gravity is given as

`\Delta g_1 = 9.95 - 9.885`

`\Delta g_1 = 0.065`

`\Delta g_2 = 9.885 - 9.82`

`\Delta g_2 = 0.065`

now mean error in both the readings is given as

`\Delta g_m = 0.065`

now percentage error is given as

`error = (\Delta g)/(g)* 100`

`error = (0.065)/(9.885) * 100`

error = 0.66 %