Question

At what speed must a 0.6 kg stone be thrown in order that it has a relativistic mass of 0.76 kg? (c = 3.00 x 10^8 m/s) (A) 0.39 c (B) 0.2847 c (C) 0.6138 c (D) 0.351c (E) 0.69768 c

Answer 1

Step-by-step explanation:

It is given that,

Relativistic Mass of the stone, m₀ = 0.6

Mass,
`m=0.76\ kg`

Relativistic mass is given by :

`m=\frac{m_o}{\sqrt{1-(v^2)/(c^2)}}`.........(1)

Where

c is the speed of light

On rearranging equation (1) we get :

`v^2=c^2(1-((m_o)/(m))^2)`

`v=c\sqrt{ (1-((m_o)/(m))^2)}`

`v=c\sqrt{ (1-((0.6)/(0.76))^2)}`

v = 0.61378 c

or

v = 0.6138 c

So, the correct option is (c). Hence, this is the required solution.