Question

A material having an index of refraction of 1.35 is used as an antireflective coating on a piece of glass (n = 1.50). What should be the minimum thickness of this film in order to minimize reflection of 560 nm light?

Answer 1

103.70 nm

Step-by-step explanation:

The minimum thickness of the film is given by
`t=(\lambda )/(4n)` where
`\lambda` is the wavelength and n is the index of the refraction

We have n =1.35

Wavelength
`\lambda =560nm`

So the minimum thickness of the film
`t=(\lambda )/(4n)=(560)/(4* 1.35)=103.70\ nm`