Question

An object's distance from a converging lens is 3.78 times the focal length. a) Determine the location of the image. Express the answer as a fraction of the focal length.

(b) Find the magnification of the image?
(c) Indicate whether it is upright or inverted?
(d) Indicate whether it is real or virtual?

Answer 1

a) v=1.36f

b)m=.36

c) real

d) Inverted

Step-by-step explanation:

a)

In this question we have given,

object distance from converging lens,u=-3.78f

focal length of converging lens,=f

we have to find location of image,v=?

and magnification,m=?

we know that u, v and f are related by following formula

`(1)/(f) =(1)/(v)- (1)/(u)`.............(1)

put values of f u in equation (1)

we got,

`(1)/(f) =(1)/(v)- (1)/(-3.78f)`

`(1)/(f)-(1)/(3.78f) =(1)/(v)`

`(2.78)/(3.78f) =(1)/(v)`

or

v=1.36f

b) Magnification,
`m=(v)/(u) \\m=(1.36f)/(3.78f)\\m=.36`

c)

Here the object is located further away from the lens than the focal point therefore image is real image and inverted.

d) image is inverted