Question

A drag racer starts from rest and accelerates at a constant 16.0m/s^2 until it reachs its top spees of 407km/hr. how far does it travel during this acceleration?

Answer 1

Distance, s = 399.42 m/s

Step-by-step explanation:

It is given that,

Initial velocity of drag racer, u = 0

Final velocity of drag racer, v = 407 km/hr = 113.056 m/s

Acceleration,
`a=16\ m/s^2`

Third equation of motion is :

`v^2-u^2=2as`

s is the distance traveled

`s=(v^2-u^2)/(2a)`

`s=(v^2)/(2a)`

`s=((113.056)^2)/(2* 16)`

s = 399.42 m/s

So, the distance traveled during this acceleration is 399.42 m/s. Hence, this is the required solution.