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How does the graph of y = 3x compare to the graph of y = 3–x?

User Getsaf
by
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2 Answers

4 votes

Answer:

Both graphs represent the equation of a line

Explanation:

Both graphs represent the equation of a straight line with the equation:

y = mx + c

Where m = the slope of the line and

c = intercept

Comparing both equations to the equation of a line given above:

In the first equation y = 3x

The slope, m = 3 (Positive slope)and

Intercept, c = 0

In the equation y = 3 -x

the slope, m = -1 (negative slope)

Intercept, c = 3

User Samtherock
by
7.4k points
2 votes

Answer and explanation:

In this problem, we have two functions. Let's call the first functions as:


y=f(x)=3x

and the second function:


y=g(x)=3-x

So we can compare this functions as follows:

  • f(x) has a positive slope while g(x) has a negative slope.

  • f(x) passes through the origin of the system of coordinates while g(x) cuts the y-intercept at
    y=3

  • g(x) has an x-intercept at
    x=3 while f(x) cuts the origin.
User Maxime Schoeni
by
7.0k points

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