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Air flows along a horizontal, curved streamline with a 22-ft radius at a streamline speed of 80 ft/s. Determine the pressure gradient normal to the streamline.

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Answer:


(dP)/(dn)= - 0.6924slug\ft2 s2

Step-by-step explanation:

data provided:

radius along which air flow = 22 ft

speed of streamline v = 80 ft/sec

we know that
-\gamma (dZ)/(dn) -(dP)/(dn) = (\rho v^2)/(R)


(dZ)/(dn) = 0As stream line is horizontal


(dP)/(dn) = - (\rho v^2)/(R)


\rho \ of\ air  = - 0.00238 slug\ft3


= - (-0.00238*80^2)/(22)


(dP)/(dn)= - 0.6924slug\ft2 s2

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