Question

Calculate the heat flux through a 1.5cm thick hardwood board, k = 0.16W/mK, with a temperature difference between the two sides of 20°C.

Answer 1

3126.9
`W/m^2`

Step-by-step explanation:

We are given that

Thermal conductivity of material ,k=0.16 W/mK

Thickness of hardwood board=[ptex]\Delta x[/tex]=1.5 cm =0.015 m

Temperature difference =
`\DeltaT=20^(\circ)`=20+273.15=293.15 k

We know that formula of heat flux

`\phi=(Q)/(A)=(k\Delta T)/(\Delta x)`

`\phi=(293.15*0.16)/(0.015)=3126.93 W/m^2`

Hence, the heat flux passing through hardwood board=3126.9
`W/m^2`