Question

What is the highest possible theoretical efficiency of a heat engine operating with a hot reservoir of furnace gases at 727°C when the cooling water available is at 27°C ?

Answer 1

`\eta_(max) = 70%`

Step-by-step explanation:

given data:

maximum temperature = 727 degree C =727 +273 = 1000 K

Minimum temperature = 27 degree C = 27 +273 = 300 K

Maximum efficiency is given as
`\eta`

`\eta = (T_(max) - T_(min))/(T_(max)) *100%`

plugging all value from the above to get maximum efficiency

`\eta = (1000-300)/(1000) *100%`

`\eta_(max) = 70%`