Question

-3---CE

AADC is formed by reflecting AABC across line segment AC, as shown in the figure.
If the length of AC is 4 units, the area of AADC is
square units.
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Answer 1

`A_(\triangle ADC)=6\ un^2 .`

Explanation:

The area of initial triangle and the area of reflected triangle are the same, so

`A_(\triangle ABC)=A_(\triangle ADC)`

Find the area of triangle ABC using formula

`A_(\triangle)=(1)/(2)\cdot \text{base}\cdot \text{height}`

In triangle ABC:

• base = AC = 4 units
• height = BE = 3 units

So,

`A_(\triangle ABC)=(1)/(2)\cdot 4\cdot 3=6\ un^2 .`

Hence,

`A_(\triangle ADC)=6\ un^2 .`