Question

THOMAS HAS A BAG WITH 77 GREEN MARBLES , 55 BLUE MARBLES. AND 44 RED MARBLES. FOR EACH PART BELOW , IF THE MARBLE SELECTED IS REPLACED BEFORE THE NEXT MARBLE IS DRAWN , FIND THE PROBABILITY FOR THE GIVEN DRAW. WRITE YOUR ANSWER AS A FRACTION ' AS A DECIMAL . AND AS A PERCENT. A RED MARBLE? A RED ORA GREEN MARBLE ? AN ORANGE MARBLE ?

Answer 1

# The probability of drawn a red marble is 1/4 , 0.25 , 25%

# The probability of drawn a red or green marble is 11/16 , 0.6875 , 68.75%

# The probability of drawn an orange marble is 0/176 , 0.0 , 0%

Explanation:

* Lets explain how to solve the problem

- Probability of any event = number of event/total out comes

- There are 77 green marbles

- There are 55 blue marbles

- There are 44 red marbles

- The marbles selected is replaced before the next marble is drawn

* Lets solve the problem

∵ There are 77 green marbles , 55 blue marbles and 44 red marbles

∴ The total number of marbles are = 77 + 55 + 44 = 176 marbles

# The probability of drawn a red marble

∵ The number of the red marbles is 44

∵ The total number of marbles is 176

∴ P(red) = 44/176 = 1/4

∵ 1/4 = 0.25

∵ 1/4 × 100 = 25%

∴ The probability of drawn a red marble is 1/4 , 0.25 , 25%

# The probability of drawn a red or green marble

- The word or in probability means add the probability of the events

∵ P(red) = 44/176

∵ The number of the green marbles is 77

∵ The total number of marbles is 176

∴ P(green) = 77/176

∴ P(red or green) = P(red) + P(green

∴ P(red or green) = 44/176 + 77/176 = 121/176 = 11/16

∵ 11/16 = 0.6875

∵ 11/16 × 100 = 68.75%

∴ The probability of drawn a red or green marble is 11/16 , 0.6875 ,

68.75%

# The probability of drawn an orange marble

∵ There is no orange marble

∴ P(orange) = 0/176 = 0

∴The probability of drawn an orange marble is 0/176 , 0.0 , 0%