Question

A certain company consists of 3 numbers followed by 3 letters. The numbers 0 and 2 are not allowed. The letters o and z are also not permitted. How many passwords are possible?

Answer 1

7,077,888

Explanation:

Of the 3 numbers, we can have 8 numbers in each position (since 0 and 2 are not allowed from the number 0 - 9 [10 digits]).

So that would be 8 * 8 * 8 different possibilities

Now,

we can have 24 letters in each position (since 0 and z are not allowed form the alphabets a - z [26 letters]).

So that would be 24 * 24 * 24 different possibilities

The number of passwords possible would be:

8 * 8 * 8 * 24 * 24 * 24 = 7,077,888