Question

The first term of an arithmetic sequence is 0 and the common difference is 12. Find the value of the 96th term of the sequence

Answer 1

`a_9_6=1,140`

Explanation:

we know that

The formula of an arithmetic sequence is

`a_n=a_1+(n-1)d`

where

`a_1` is the first term

`a_n` is the nth term

n is the number of terms

d is the common difference

we have

`n=96\\ d=12`

`a_1=0`

substitute the given values

`a_9_6=0+(96-1)(12)`

`a_9_6=1,140`