Question

7. While prospecting in the North Woods, Joe found a gold nugget which had a density of 19.2 g/cm3. Joe dropped the gold into water in a graduated cylinder, the water level increased by 15.0 mL. How many grams of gold did he have? (Ans: 288 g)

Answer 1

• m = 288 g

Step-by-step explanation:

1) Data:

a) d = 19.2 g/cm³

b) ΔV water = 15.0 ml

c) m = ?

2) Principles and formula:

• density = mass / volume

d = m / v

• The volume of water displaced, i.e. the increase in the level of water, is equal to the volume of the gold nugget submerged.

• The unit ml (mililiter) is equal to the unit cm³

3) Solution:

a) v = ΔV water = 15.0 ml = 15 cm³

b) d = m / v ⇒ m = d × v = 19.2 g/cm³ × 15 cm³ = 288 g.