Question

A certain pendulum oscillates back and forth every 3.00s . What would the new period be, in s , if the pendulum were one-half of its original length?

Answer 1

2.122 second

Step-by-step explanation:

T1 = 3 s

L1 = L

L2 = L/2

As we know the time period of a simple pendulum is related by the length of the pendulum as

`T =2\pi \sqrt{(L)/(g)}`

Here, only the length of pendulum changes and the value of g is constant so,

`(T_(2))/(T_(1)) =\sqrt{(L_(2))/(L_(1))}`

`(T_(2))/(3) =\sqrt{(L)/(2L)}`

T2 = 2.122 second