Answer:
The energy in electron volts of a single photon of these X‑rays is 46697.5 eV.
Step-by-step explanation:
Given that,
Wavelength = 0.0265 nm
We need to calculate the energy
Using formula of energy
![E=(hc)/(\lambda)](https://img.qammunity.org/2020/formulas/physics/middle-school/qsv4fkctsmfst9aln3wy2xtnfdwqn1eov2.png)
Where, h = plank constant
c = speed of light
= wavelength
Put the value into the formula
![E=(6.6*10^(-34)*3*10^(8))/(0.0265*10^(-9))](https://img.qammunity.org/2020/formulas/physics/college/nyaxw3x50yki2j95hb9b0hbim1fpbej0w0.png)
![E=7.4716*10^(-15)\ J](https://img.qammunity.org/2020/formulas/physics/college/6bzlylwfh5jpxt85yb7u9u7mszesrhonim.png)
We know that,
![1 eV = 1.6*10^(-19)\ J](https://img.qammunity.org/2020/formulas/physics/college/isomqbeffg8amn5i1y30n57r3revbqxnxd.png)
The energy in eV
![E=(7.4716*10^(-15))/(1.6*10^(-19))](https://img.qammunity.org/2020/formulas/physics/college/4050zpho5oxyd2vdsi2b6fms74gimek7qf.png)
![E=46697.5\ eV](https://img.qammunity.org/2020/formulas/physics/college/7s2x2yomnf19xnr93vb3xyq8z0g3u2a1u6.png)
Hence, The energy in electron volts of a single photon of these X‑rays is 46697.5 eV.