Answer:
The time it will take the mega-ray blaster to hit the ground is 2.57 s.
Step-by-step explanation:
Given;
initial velocity of Optimus Prime, u = 24 m/s
height of fall of the mega-ray blaster, h = 94 m
The time of fall of the mega-ray blaster is calculated using the following kinematic equation;
![h = ut + (1)/(2)gt^2\\\\94 = 24t + (1)/(2)(9.8)t^2\\\\94 = 24t + 4.9t^2\\\\4.9t^2 +24t -94 = 0\\\\Use \ formula \ method \ to \ solve \ for \](https://img.qammunity.org/2022/formulas/physics/college/rw40hy39suh9x2awnnfwvueuveuc442lj5.png)
![t = 2.57 \ s \ \ or \ \ t = -7.47 \ s](https://img.qammunity.org/2022/formulas/physics/college/uy8qf14p8mqasu84968gl4lul9c1184xc9.png)
t = 2.57 s
Therefore, the time it will take the mega-ray blaster to hit the ground is 2.57 s.