Question

Help me please!!!!!! I don’t know it

Answer 1

A

Explanation:

Given a parabola in standard form : y = ax² + bx + c : a ≠ 0

Then the x- coordinate of the vertex is

`x_(vertex)` = -
`(b)/(2a)`

y = 2x² + 16x + 33 ← is in standard form

with a = 2 and b = 16, thus

`x_(vertex)` = -
`(16)/(4)` = - 4

Substitute x = - 4 into the equation for the corresponding value of y

y = 2(- 4)² + 16(- 4) + 33 = 32 - 64 + 33 = 1

vertex = (- 4, 1 )

To find the y- intercept let x = 0 in the equation

y = 2(0)² + 16(0) + 33 = 0 + 0 + 33 = 33

y- intercept = (0, 33 )