Answer:
1.6537 * 10^9
Step-by-step explanation:
Given that :
Distance (r) = 2.56 × 10^7 m
Using the relation from Kepler's third law of motion :
T2 = [ 4* pi^2/ G (M1 + M2) ]r^3
M1 = mass of earth = 5.97 *10^24
M2 = Mass of satellite = 9.0 × 10^3 kg
G = Gravitational constant = 6.67 *10^-11
T2 = [ (4 x 3.14^2) / 6.67 x 10^-11 ( 9 x 10^3 + 5.97 x 10^24)]/ (2.56 x 10^7)^3
= 1.6537 * 10^9