Question

EX 6-1 A ball is twirled on a 0.870 - m-long string with a constant speed of 3.36 m / s . Calculate the acceleration of the ball. Be sure to specify the direction of the acceleration.

Answer 1

`a=12.97\ m/s^2`

Step-by-step explanation:

Given that,

The length of a string, l = 0.87 m

Speed of the ball, v = 3.36 m/s

We need to find the acceleration of the ball. The acceleration acting on the ball is centripetal acceleration. It is given by :

`a=(v^2)/(r)\\\\a=((3.36)^2)/(0.87)\\\\=12.97\ m/s^2`

So, the acceleration of the ball is
`12.97\ m/s^2`.