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What simple interest rate is needed for $6,000 to earn $1,000 in 15 months

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let's recall that a year has 12 months, so 15 months is really 15/12 years.


\bf ~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill&\$1000\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to r\%\to (r)/(100)\\ t=years\to (15)/(12)\dotfill &(5)/(4) \end{cases}


\bf 1000=(6000)r\left( \cfrac{5}{4} \right)\implies 1000=7500r\implies \cfrac{1000}{7500}=r\implies \cfrac{2}{15}=r \\\\\\ \stackrel{\textit{converting that to a percentage}}{\cfrac{2}{15}\cdot 100 = r\implies \cfrac{40}{3}=r}\implies \stackrel{\%~\hfill }{13.\overline{3}}=r

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