Question

A car initially traveling at 24 m/s slams on the brakes and moves forward 196 m before coming to a complete halt. What was the magnitude of the car's deceleration? A = 1.47 m/s 2

Answer 1

`-1.47 m/s^2`

Step-by-step explanation:

We can use the following SUVAT equation to solve the problem:

`v^2 - u^2 = 2ad`

where

v = 0 is the final velocity of the car

u = 24 m/s is the initial velocity

a is the acceleration

d = 196 m is the displacement of the car before coming to a stop

Solving the equation for a, we find the acceleration:

`a=(v^2-u^2)/(2d)=(0-(24)^2)/(2(196))=-1.47 m/s^2`