Question

If g(x)=5x-3 and h(x)= sqaure root of x find (g o h)(4)

Answer 1

Answer:
`(g o h)(4)=7`

Explanation:

Given the function g(x):

`g(x)=5x-3`

And the function h(x):

`h(x)=√(x)`

We need to plug the function
`h(x)=√(x)` into the function
`g(x)=5x-3`, in order to find
`(g o h)(x)` . Then:

`(g o h)(x)=5(√(x))-3`

`(g o h)(x)=5√(x)-3`

Now, in order to find
`(g o h)(4)`, we need to substitute
`x=4` into
`(g o h)(x)=5√(x)-3`. Then, this is:

`(g o h)(4)=5√(4)-3`

`(g o h)(4)=10-3`

`(g o h)(4)=7`

Answer 2

The answer is 7

Explanation:

We have:

if g(x)=5x-3 and h(x)= sqaure root of x.

We have to find (g o h)(4).

(g o h) = g(h(x))

Plug the value of h(x) which is √x in g(x)

g(h(x))= g(√x)

Now plug the value √x in g(x).

g(h(x))= g(√x) = 5√x-3

Now to find (g o h)(4) plug in 4 in place of x

(g o h)(x)=g(h(x))= g(√x) = 5√x-3

(g o h)(4)= g(h(4)) = g(√4) = 5√4-3

Therefore:

(g o h)(4) = 5(2)-3

(g o h)(4) = 10-3 = 7

Thus the answer is 7....