Question

A Nov-Dec power bill shows that a home uses 1355 kwh over a 30-day period. Find the energy used (in kJ) for the 30-day period.

Answer 1

To calculate the energy used in kilojoules for the 30-day period, multiply the consumption in kWh (1355 kWh) by 3.6 x 10^6 J to convert to joules, and then divide by 1000 to get kilojoules, resulting in 4,878,000 kJ.

Step-by-step explanation:

To find the energy used in kilojoules (kJ) for the 30-day period, we need to convert the energy consumption from kilowatt-hours (kWh) to joules (J) first and then to kilojoules. We know that 1 kWh equals 3.6 million joules (3.6 x 106 J). Therefore, the energy used by a home that consumes 1355 kWh over a 30-day period is:

1355 kWh × 3.6 x 106 J/kWh = 4,878,000,000 J

Since 1 kJ is 1000 J, we convert joules to kilojoules by dividing by 1000:

4,878,000,000 J ÷ 1000 J/kJ = 4,878,000 kJ

Therefore, the home uses 4,878,000 kJ of energy over the 30-day period.

Answer 2

The energy used for the 30-day period is 4878000 kilojoules.

Step-by-step explanation:

According to the power bill, 1355 kilowatt-hours was used over a 30-day period. A kilowatt-hour is equal to 3600 kilojoules. Then, we calculate the energy used, measured in kilojoules, is determined by simple rule of three:

`E = 1355\,kWh* (3600\,kJ)/(1\,kWh)`

`E = 4878000\,kJ`

The energy used for the 30-day period is 4878000 kilojoules.