Question

If you have a 1.0 m aqueous solution of NaCl, by how much will it increase the water’s boiling point, if KB = 0.512 °C/m? In other words, what is the boiling point elevation (increase)?

Answer 1

Answer: The elevation in boiling point is 1.024°C.

Step-by-step explanation:

To calculate the elevation in boiling point, we use the equation:

`\Delta T_b=ik_b* m`

where,

i = Van't Hoff factor = 2 (for NaCl)

`\Delta T_b` = change in boiling point = ?

`k_b` = boiling point constant =
`0.512^oC/m`

m = molality = 1.0 m

Putting values in above equation, we get:

`\Delta Tb=2* 0.512^oC/m* 1.0m\\\\\Delta Tb=1.024^oC`

Hence, the elevation in boiling point is 1.024°C.