Question

The normal lead content in human blood is about 0.40 ppm (parts per million, meaning 0.40 g of lead for each million grams of blood). How much lead would be present in 6.0×103 g of blood?

Answer 1

`2.4x10^(-3)`

Step-by-step explanation:

We can solve this equation in a lot of different ways, the easiest equation is called ruled of three, and it's solved as follows:

`1000000g/0.40g = 6(10)^(3) /x` this is an equality of the information that has been given to us, and we solve it algebraically.

X = How much lead would be present in 6.0×103 g of blood

`x (1000000)g/0.40g =6(10)^(3)g`

`x=6(10)^(3)g 0.40g/1000000g=2.4x10^(-3)g`

And that's how we conclude the lead content in 6*10^3g blood

Answer 2

Lead in
`6.0 * 10^(3)\\`g of blood
`= 2.4 * 10^(-3)`grams

Step-by-step explanation:

Given -

Amount of lead in human blood -
`0.40` parts per million (ppm)

This is equivalent to
`0.40` g of lead for each million grams of blood

Numerically, it can be represented as -

`(0.40)/(1*10^6) (g)/(million gram)`

Lead in
`6.0 * 10^(3)\\`g of blood

`= (0.40)/(10^6) * 6.0 * 10^3\\= 2.4 * 10^(-3)` grams

Lead in
`6.0 * 10^(3)\\`g of blood
`= 2.4 * 10^(-3)`grams