Answer:
h =12.9 w/m2 k
Step-by-step explanation:
we know that thermal conductivity of air K at 0 degree celcius = 0.024 w/mk
T_S = 80 Degree celcius
temperature gradient = -43 degree C/mm = - 43*1000 / m
![(dT)/(dx) = - 43*1000 / m](https://img.qammunity.org/2020/formulas/physics/college/c3yb8ibj2d5akt6u200fpsutsn740j9zw1.png)
by fourier law
![Q = -k_(air) A * (dT)/(dx)](https://img.qammunity.org/2020/formulas/physics/college/pdy3ia32kzin3pq5g2n4hgo8i1seshff2g.png)
![(Q)/(A) = -0.024 *1*(-43000)](https://img.qammunity.org/2020/formulas/physics/college/e37uaxkcjw1fet5wujxcjy5wg7mum45nvd.png)
q = 1032 watt/m2
we know that from newton's law
q = h (T_s - T_∞)
1032 = h*(80 - 0)
h =12.9 w/m2 k