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The formation of condensation on a glass of ice water causes the ice to melt faster than it would otherwise. If 8.00 g of condensation forms on a glass containing both water and 200 g of ice, how many grams of the ice will melt as a result?

User Thbonk
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8.7k points

1 Answer

2 votes

Step-by-step explanation:

It is known that heat (Q) required to change the phase of a given sample of mass m will be as follows.


Q_(f) = mL_(f) ........ (1)

where,
L_(f) = latent heat of fusion

Similarly,
Q_(v) = mL_{v}[/tex] ....... (2)

where,
L_(v) = latent heat of vaporization

As it is known that value of latent heat of fusion of water is 334 J/g and latent heat of vaporization of water is 2260 J/g.

Hence, equating both the equations as follows.


m_(condensation) * L_(v) =
m_(fusion) * L_(f)


m_(fusion) =
(m_(condensation) * L_(v))/(L_(f))

=
(8 g * 2260 J/g)/(334 J/g)

= 54.13 g

Hence, we can conclude that 54.13 grams of ice will melt.

User Jeff Davis
by
8.2k points
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