Question

The formation of condensation on a glass of ice water causes the ice to melt faster than it would otherwise. If 8.00 g of condensation forms on a glass containing both water and 200 g of ice, how many grams of the ice will melt as a result?

Answer 1

Step-by-step explanation:

It is known that heat (Q) required to change the phase of a given sample of mass m will be as follows.

`Q_(f) = mL_(f)` ........ (1)

where,
`L_(f)` = latent heat of fusion

Similarly,
`Q_(v)` = mL_{v}[/tex] ....... (2)

where,
`L_(v)` = latent heat of vaporization

As it is known that value of latent heat of fusion of water is 334 J/g and latent heat of vaporization of water is 2260 J/g.

Hence, equating both the equations as follows.

`m_(condensation) * L_(v)` =
`m_(fusion) * L_(f)`

`m_(fusion)` =
`(m_(condensation) * L_(v))/(L_(f))`

=
`(8 g * 2260 J/g)/(334 J/g)`

= 54.13 g

Hence, we can conclude that 54.13 grams of ice will melt.