Answer:
Speed of the canoe in still water is 7 miles per hour and speed of the river stream will be 1 miles per hour.
Explanation:
Let the speed of canoe paddled by Jason in still water is x miles per hour and speed of the river current y miles per hours.
As per statement of the question,
Resultant speed of canoe upstream = (x - y)
and speed of canoe with the stream = (x + y)
Now as per statement,
![(x - y)=(24)/(4)](https://img.qammunity.org/2020/formulas/mathematics/high-school/zfxpbd75ki6div8dvtu12poc70ljh865v8.png)
x - y = 6 ------(1)
and
![(x + y)=(24)/(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/6hensp6exdx36szgcqdmpn1dq615ksjnzz.png)
x + y = 8 ------(2)
Now we add equation 1 and 2.
(x - y) + (x + y) = 6 + 8
2x = 14
x = 7
By putting x = 7 in equation 2
7 + y = 8
y = 8 - 7
y = 1
Therefore, Speed of the canoe in still water is 7 miles per hour and speed of the river stream will be 1 miles per hour.