Question

Two ships leave a harbor at the same time. One ship travels on a bearing S 15 degrees W at 10 miles per hour. The other ship travels on a bearing N 75 degrees E at 11 miles per hour. How far apart will the ships be after 2 ​hours?

Answer 1

The distance between the ships after 2 hours will be 36.38 miles.

Step-by-step explanation:

Given that,

One ship travels on a bearing S 15 degrees W at 10 miles per hour.

The other ship travels on a bearing N 75 degrees E at 11 miles per hour.

After 2 hour,

One ship covered the distance is 20 miles.

Other ship covered the distance is 22 miles.

We need to calculate the distance between the ships

Using cosine rule

`c^2=a^2+b^2-2ab\cos\theta`

Put the value into the formula

`c^2=20^2+22^2-2*20*22\cos120`

`c^2=1324`

`c=36.38`

Hence, The distance between the ships after 2 hours will be 36.38 miles.