Question

A conveyor belt is used to send burgers through a grill- ing machine. If the grilling machine is 1.2m long and the burgers require 2.8min to cook, how fast must the conveyor belt travel? If the burgers are spaced 25 cm apart, what is the rate of burger production (in burgers/min)?

Answer 1

`Rate = 1.71 burger/min`

Step-by-step explanation:

Length of the conveyor belt is given as

`L = 1.2 m`

time taken to cook one burger is given as

`t = 2.8 min = 168 s`

now we can find the speed of the belt as

`v = (distance)/(speed)`

`v = (1.2)/(168)`

`v = 7.14 * 10^(-3) m/s`

Now we know that the distance between two burgers is given as 25 cm

`d = 0.25 m/burger`

now the production rate of burgers is given as

`Rate = (v)/(d)`

`Rate = (7.14 * 10^(-3) m/s)/(0.25 m/burger)`

`Rate = 0.0286(burger)/(sec)`

`Rate = 0.0286* 60(burger)/(min)`

`Rate = 1.71 burger/min`