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(4j3 - 7j + 2s3 ) - ( - 12j3 - 8j )

It’s basic operations with variables what’s the answer please help

User Zaw
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1 Answer

2 votes

Answer:


-8j^3+j+2s^3

Explanation:

The trick here is to consider
j^3,
j, and
s^3 as separate variables.


(4j^3-7j+2s^3)-(-12j^3-8j)


4j^3-7j+2s^3+12j^3+8j


4j^3+12j^3-7j+8j+2s^3


16j^3+j+2s^3

User Ahmed Al Jabry
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