Question

What is the solubility of 80 grams of magnesium chloride (MgCl2) dissolved into 150 cm3 of water?

Answer 1

5.6 moldm^-3

Step-by-step explanation:

Solubility refers to the the amount of solute that can dissolve in 1000cm3 of solution.

Number of moles of MgCl2= mass / molar mass

Molar mass of MgCl2 = 24+ 2(35.5)= 95gmol-1

Number of moles= 80g/95gmol-1= 0.842 moles

If 0.842 moles dissolves in 150cm^3 of water

x moles dissolves in 1000cm^3 of water

x= 0.842×1000/150

x= 5.6 moldm^-3

Answer 2

=53.3g/100g water

Step-by-step explanation:

Solubility= (Mass of solute×100g solvent)/ mass of solent.

Mass of solute=80 grams

Mass of solvent=150g (assuming that the density of water is 1g/cm³)

Thus solubility= (80g×100g)/150g

=53.3g/100g water

Solubility of Magnesium in water at the given temperature is 53.3g/100g