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Find the center and radius of the circle with equation (x + 3)^2 + (y – 6)^2 = 100.

Find the center and radius of the circle with equation (x + 3)^2 + (y – 6)^2 = 100.-example-1

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Answer:

center (-3,6)

radius(r) 10

Explanation:

The center-radius form (it is really called standard form) of a circle is:


(x-h)^2+(y-k)^2=r^2

where
(h,k) is the center and
r is the radius.

Compare the following:


(x-h)^2+(y-k)^2=r^2


(x+3)^2+(y-6)^2=100

You should see the following:


-h=3


-k=-6


r^2=100.


-h=3 \text{ implies }h=-3.


-k=-6 \text{ implies } k=6.


r^2=100 \text{ implies } r=√(100)=10.

So the center is (-3,6) and the radius is 10.

User Redrah
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