Question

In the given figure AD is median. prove that ar(triangle ABD) = ar(triangle ACD)

Answer 1

Proved!

Explanation:

We know that,

`\bigstar\; \boxed{\sf {Area\; of\; triangle= (1)/(2) * Base * Height\;(1)/(2) * Base * Height}}`

So,

`\it Area\; of\; triangle, ABD= (1)/(2) * BD * AN12* BD * AN`

And,

`\it Area\; of\;triangle\;ADC= (1)/(2) * DC * AN =12 * BD * AN\;(1)/(2) * DC * AN = 12 * BD *AN`

(As we know BD = DC )

So,

Area of triangle ABD = Area of triangle ADC

(Hence proved)

`\rule{300}{1.5}`

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