Question

Can someone help w/ d plz

Answer 1

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Answer:

`\large\boxed{0}`

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Explanation:

We are solving the expression:
`(2*(3+(2-1)))/(4-(6+2)) -(3-5)`

Solve:

`(2*(3+(2-1)))/(4-(6+2)) -(3-5)\\\\\text{Lets start with the fraction}\\\\(2*(3+(2-1)))/(4-(6+2)) -(3-5)\\\\(2*(3+(1)))/(4-(8)) -(3-5)\\\\(2*(4))/(-4) -(3-5)\\\\(8)/(-4) -(3-5)\\\\-2 -(3-5)\\\\\text{Distrubute the negative to the numbers inside the parenthesis}\\\\-2 -3+5\\\\-5+5\\\\\boxed{0}`

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