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What is the equation of the line that is parallel to the given line and passes trough the point (2,3)?

What is the equation of the line that is parallel to the given line and passes trough-example-1
User DarkAnt
by
5.6k points

2 Answers

2 votes

Answer:

The answer is c

Explanation:

User Frank Borzage
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5.0k points
6 votes

Answer:


y=(-1)/(2)x + 4

Explanation:

First we need to find the slope of the given line, the one that is passing trough the points (-4,0) and (4,-4).

For that, lets use the slope`s equation
(y_(2)-y_(1))/(x_(2)-x_(1))

m= (-4-0) / (4-(-4)) = -1/2

A line that is parallel to this one must have its same slope, so m2= -1/2

Now, lets find the 'y' axis intercept point using the point given: (2,3)

And the equation for lines: y=mx+b

By evaluating (2,3) in the above expression we have:

3=-1/2 * 2 +b

From here, we obtain that b=4

Hence, our line is y=-1/2 * x + 4

User ShAkKiR
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