Question

The circle below is centered at the point (4,1) and has a radius of length 2. What is it’s equation?

Answer 1

B

Explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

here (h, k ) = (4, 1) and r = 2, hence

(x - 4)² + (y - 1)² = 4 → B

Answer 2

Option B:

`(x-4)^2+(y-1)^2 = 4`

Explanation:

Given

Centre = (h,k) = (4,1)

Radius = r = 2

The standard equation of circle is:

`(x-h)^2+(y-k)^2=r^2`

Putting the values of h,k and r

`(x-4)^2+(y-1)^2 = (2)^2\\(x-4)^2+(y-1)^2 = 4`

Hence, the correct option is option B

`(x-4)^2+(y-1)^2 = 4`