146,380 views
28 votes
28 votes
(5x - 2)^2 = 27 quadratic formula

User Benjamin Solum
by
2.8k points

1 Answer

11 votes
11 votes

Answer:


x = (2 \pm 3\sqrt3)/(5)

Explanation:

Hello!

First, expand the equation:


  • (5x - 2)^2 = 27

  • (5x - 2)(5x - 2) = 27

  • 25x^2 - 10x - 10x + 4 = 27

  • 25x^2 - 20x -23 = 0

Standard form of a Quadratic:
ax^2 + bx + c = 0

Quadratic Formula:
x = (-b \pm √(b^2 - 4ac))/(2a)

Given our Equation:
25x^2 - 20x -23 = 0

  • a = 25
  • b = -20
  • c = -23

Solve the Quadratic


  • x = (-b \pm √(b^2 - 4ac))/(2a)

  • x = (20 \pm √(20^2 - 4(25)(-23)))/(2(25))

  • x = (20 \pm √(400 +2300))/(50)

  • x = (20\pm√(2700))/(50)

  • x = (20\pm30\sqrt3)/(50)

  • x = (10(2 \pm3\sqrt3))/(10(5))

  • x = (\\ot10(2 \pm3\sqrt3))/(\\ot10(5))

  • x = (2 \pm 3\sqrt3)/(5)

The solutions are
x = (2 + 3\sqrt3)/(5) and
x = (2 - 3\sqrt3)/(5).

User Scottdavidwalker
by
2.8k points