Question

Please help i dont get this at all

Answer 1

`(20y^(2) a^(2) )/(41bx^(3) )`

Explanation:

1) Flip the second fraction and change the operation to multiplication:

`(5x^(2)y^(3)  )/(2a^(5)b^(4)  ) *  (8a^(7)b^(3)  )/(41x^(5)y  )`

2) Cross cancel factors:

`(5y^(2)   )/(2b  ) *  (8a^(2)  )/(41x^(3)  )`

3) Multiply:

`(40y^(2) a^(2) )/(82bx^(3) )`

4) Simplify:

`(20y^(2) a^(2) )/(41bx^(3) )`

Answer 2

The correct option is D)
`(20y^2a^2)/(41x^(3)b)`.

Explanation:

Consider the provided expression.

`(5x^2y^3)/(2a^5b^4)/ (41x^5y)/(8a^7b^3)`

Apply the fraction rule:
`(a)/(b)/ (c)/(d)=(a)/(b)* (d)/(c)`

Change the expression by using the above rule:

`(5x^2y^3)/(2a^5b^4)* (8a^7b^3)/(41x^5y)`

`(5x^2y^3* \:8a^7b^3)/(2a^5b^4* \:41x^5y)`

`(40a^7y^3b^3x^2)/(82a^5x^5b^4y)`

`(20a^7y^3b^3x^2)/(41a^5x^5b^4y)`

Apply the exponent rule:
`(x^a)/(x^b)=(1)/(x^(b-a))`

`(20a^(7-5)y^(3-1)b^(3-4)x^(2-5))/(41)`

`(20a^2y^2b^(-1)x^(-3))/(41)`

Again apply the exponent rule:

`(20y^2a^2)/(41x^(3)b)`

Hence, the correct option is D)
`(20y^2a^2)/(41x^(3)b)`.